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View Diary: Seawater + electricity = jet fuel (15 comments)

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  •  thanks for explaining yourself (0+ / 0-)

    As it happens I am an electrical engineer.  The process of breaking the O-H bond itself is close to lossless and almost the same energy is released upon recombining, in combustion or a fuel cell. Efficiencies as high as 96% have been reported experimentally although commercial operations are much less efficient.

    Losses are incurred due to the electrical resistance, "R" encountered by the electrolysis current, "I", on the way to breaking that bond. This causes a voltage drop V = I*R known as "IR drop".  That is where the inefficiency comes in.

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