Skip to main content

View Diary: BP Deepwater Oil Spill Quantitative Data (52 comments)

Comment Preferences

  •  Section: Pressures (7+ / 0-)

    Water Pressure at 5067 feet below see level (BOP): 2266PSI
    http://www.calctool.org/...
    Or using
       units v 1 5067ft*1.025g/cm^3*1gravity+1atmosphere psi
    5067ft*1.025g/cm^3*1gravity+1atmosphere = 2266.2969 psi
    Note that this value doesn't take into account the increase in density at depth (water is not entirely incompressible) or water temperature.

    Specific gravity of Sea Water is 1.025 g/cm^3 but may vary from 1.020 to 1.029 depending on temperature and salinity.   It can also increase to 1.050g/cm^3 at deep depths.
    http://en.wikipedia.org/...

    Formation pressure (bottom of well) is often mentioned as 13,000PSI.
     
    Pressure at well head with oil flowing (before riser cut off): 8000...9000PSI
    http://adropofrain.net/...
    Note that pressure will increase up to formation pressure minus column weight under no-flow conditions.
     
    Some rough calculations from the same link:

    Hypothetical calculations – based on well 13,000 feet below the BOP and a formation pressure of 13,000 psi.
    Well full of gas – pressure on BOP about 13,000 psi
    Well full of oil – pressure on BOP about 8,250 psi
    Well full of 18.5 lb mud – pressure on BOP 0 psi = no flow

    I get different numbers for pressure above water pressure (zero flow)
    Well full of oil with assumed density of 0.8g/cm^3
    13000psi-2266psi-(17168ft-5067ft)*0.8g/cm^3*1gravity = 6537.1069 psi
    Well full of water
    13000psi-2266psi-(17168ft-5067ft)*1g/cm^3*1gravity = 5487.8837 psi
    Well full of 18.5ppg mud (overfilled):
    13000psi-2266psi-(17168ft-5067ft)*18.5pound/gallon*1gravity = -895.53247 psi
    Well full of 16.5ppg mud
    13000psi-2266psi-(17168ft-5067ft)*16.5pound/gallon*1gravity = 361.71429 psi

    A long comment on oil drum on pressures with plots:
    http://www.theoildrum.com/...

    Assuming an oil density of 0.8, pressure drop from the new riser to sea level would be:
    5067ft*0.8g/cm^3*1gravity = 1757.3471 psi

    Assuming an oil density of 0.8, pressure drop from the cement leak at 17168 feet below sea level to the well head/bop at 5067 feet would be:
    17168ft-5067ft)*0.8g/cm^3*1gravity = 4196.8931 psi

    And with 16.5 pound per gallon mud, the density would be:
    (17168ft-5067ft)*16.5pound/gallon*1gravity = 10372.286 psi

Subscribe or Donate to support Daily Kos.

  • Recommended (149)
  • Community (71)
  • Baltimore (68)
  • Bernie Sanders (49)
  • Freddie Gray (38)
  • Civil Rights (38)
  • Elections (27)
  • Hillary Clinton (27)
  • Culture (24)
  • Racism (23)
  • Education (20)
  • Labor (20)
  • Media (19)
  • Law (19)
  • Economy (19)
  • Rescued (18)
  • Science (16)
  • 2016 (15)
  • Politics (15)
  • Riots (14)
  • Click here for the mobile view of the site